题目如下：

We are given that the string "abc" is valid.

From any valid string V, we may split V into two pieces X and Y such that X + Y (X concatenated with Y) is equal to V.  (X or Y may be empty.)  Then, X + "abc" + Y is also valid.

If for example S = "abc", then examples of valid strings are: "abc", "aabcbc", "abcabc", "abcabcababcc".  Examples of invalid strings are: "abccba", "ab", "cababc", "bac".

Return true if and only if the given string S is valid.

 

Example 1:

Input: "aabcbc"Output: trueExplanation: We start with the valid string "abc".Then we can insert another "abc" between "a" and "bc", resulting in "a" + "abc" + "bc" which is "aabcbc".

Example 2:

Input: "abcabcababcc"Output: trueExplanation: "abcabcabc" is valid after consecutive insertings of "abc".Then we can insert "abc" before the last letter, resulting in "abcabcab" + "abc" + "c" which is "abcabcababcc".

Example 3:

Input: "abccba"Output: false

Example 4:

Input: "cababc"Output: false

 

Note:

1. 1 <= S.length <= 20000
2. S[i] is 'a', 'b', or 'c'

解题思路：这个题目有点用巧的意思了，可以逆向思维。每次从input中删除掉一个"abc"，如果最后input能变成空就是True，否则就是False。

代码如下：

class Solution(object):    def isValid(self, S):        """        :type S: str        :rtype: bool        """        while len(S) > 0:            inx =  S.find('abc')            if inx == -1:                return False            S = S[:inx] + S[inx+3:]        return True